According to your diagram, you assume that AB = BE = DF = CD. However, this does not work for all cases. If you do refer to my diagram, AB = CD, BE = DF, AB ≠ BE.Hao Yang
According to your diagram, you assume that AB = BE = DF = CD. However, this does not work for all cases. If you do refer to my diagram, AB = CD, BE = DF, AB ≠ BE.
ReplyDeleteHao Yang